36x^2+121x=0

Solution for 36x^2+121x=0 equation:

36x^2+121x=0

a = 36; b = 121; c = 0;
Δ = b2-4ac
Δ = 1212-4·36·0
Δ = 14641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14641}=121$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-121}{2*36}=\frac{-242}{72}
=-3+13/36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+121}{2*36}=\frac{0}{72}
=0
$